|  | SUMMARY = "A Python Interface To The cURL library" | 
|  | DESCRIPTION = "\ | 
|  | PycURL is a Python interface to libcurl, the multiprotocol file \ | 
|  | transfer library. Similarly to the urllib Python module, PycURL can \ | 
|  | be used to fetch objects identified by a URL from a Python program \ | 
|  | " | 
|  | SECTION = "devel/python" | 
|  | HOMEPAGE = "http://pycurl.io/" | 
|  |  | 
|  | LICENSE = "LGPLv2 | MIT" | 
|  | LIC_FILES_CHKSUM = " \ | 
|  | file://COPYING-LGPL;md5=4fbd65380cdd255951079008b364516c \ | 
|  | file://COPYING-MIT;md5=2df767ed35d8ea83de4a93feb55e7815 \ | 
|  | " | 
|  |  | 
|  | SRC_URI[md5sum] = "f0ed4c805e8bec734990e2e0ee78568e" | 
|  | SRC_URI[sha256sum] = "6f08330c5cf79fa8ef68b9912b9901db7ffd34b63e225dce74db56bb21deda8e" | 
|  |  | 
|  | inherit pypi | 
|  |  | 
|  | PYPI_PACKAGE = "pycurl" | 
|  |  | 
|  | DEPENDS = "\ | 
|  | curl \ | 
|  | ${PYTHON_PN}\ | 
|  | " |